cc As you can see, DMAIC is the real structure of Six Sigma.
Now, I would like to illustrate two examples of Construction projects compatible with DMAIC as follows:
Example (1): An executive method for embankment layers in roads and yards
Define of the problem (D phase):
In this example, I have tried to show what is the distance between two consecutive soil storage area that they have been unloaded by Damp Trucks for reaching to designing specifications in the roads and yards.
It is possible only with having results of laboratory tests.
Easily, we can see that above problem is independent of optimum moisture. When we proceed to execute a compacted layer, for example: soil, Base, Sub base layer in road and yards, we should know how much the soil or aggregate (as a base or sub base layer) per square meter is need for reaching to specifications of design (thickness, percentage of compaction).
Measure phase (M):
In this phase we approach on validate and refine problem accompanied by measuring of requirements. In this example it has been raised: “what is the distance between unloading of two consecutive Damp Trucks a long road so that two important specifications are produced?”
What are the two important specifications? (Measuring of requirements)
After designing of a pavement for roads or yards, civil engineer obtains several layers of aggregates (base or sub base) and soil that they must be compacted and executed under asphalt. Each one of these layers has its own specifications included: thickness, percentage of compaction, maximum dry density, optimum moisture, atterburg limits, sandy equalent, crashing percentage and etc.
Two specifications of them are very important: thickness and compaction percentage.
Analysis phase (A):
In order to execute a filling layer on sub grade in the road, we start it in accordance with four stages as follows:
A) Unloading of soil or aggregate on required area (XY) of sub grade with required volume (V1) by a Damp Truck.
B) To distribute storage area of soil (Unloaded by Damp Truck) by a Grader so that the soil or aggregate layer reaches to thickness of design specifications.
A) Spraying on soil by watering - Can Truck in order to reach the soil or aggregate to optimum moisture.
B) To compact the soil or aggregate by a Roller in order to reach to compaction percentage of design specifications.
In this analysis, the target is to obtain the required area (XY) for unloading soil of each Damp Truck or the required volume (V1) of unloading soil on area (XY) by each Damp Truck for reaching to specifications of design.
Improve phase (I):
In this phase, we should develop our idea to remove root cause or to solve the problem in which we have to use some tests and standards. At the first, we should define some parameters in accordance with the standards as follows:
- w% Natural moisture of the soil
- Dn Natural unit weight (Free unit weight of the soil)
- Dm Maximum dry density
- R % Compaction Percentage (Design Specification)
- Z Thickness of layer (Design specification)
- V2 Volume of dry compacted soil after filling
- m2 Weight of dry compacted soil after filling
- m1 Weight of natural soil (Free)
- A required Area (XY) for unloading soil of each Damp Truck
- V1 required Volume of unloading soil on Area (XY) by each Damp Truck
In order to solve above problem, I has used from returning analyze as follows:
An element of soil (X, Y, Z) has been considered after executing of the last stage (stage D).
Where:
V2 = Z.X.Y (1)
m2 = Dm. Z.X.Y.R (2)
m1 = m2 + (m2 * w %) = m2 (1 + w %) (3)
Therefore, it could be used from below formula:
V1 = m1 / Dn= Dm.Z.X.Y.R((1 + w %) / Dn (4)
X.Y = A = V1. Dn / Dm.Z.R((1 + w %) (5)
Now, we can solve two samples as follows:
Sample (1):
w = 3 %
Dm = 2.17 gr / cm3
R = 95 %
Dn = 1.53 gr / cm3
A = 10000 cm2
Z=15Cm
V1 = 2.17 * 15 * 10000 * 95 % * (1 + 3 %) / 1.53
V1 = 0.2 m3
Sample (2):
w = 3 %
Dm = 2.17 gr / cm3
R = 95 %
Dn = 1.53 gr / cm3
V1 = 6 m3 = 6000,000 cm3
Z=15Cm
6000,000 = 2.17 * 15 * 95 % * (1 + 3 %) A / 1.53
A = X.Y= 288226 cm2
A # 29 m2
Control phase (C):
In this phase, we proceed toward to check and control our solution by executing real job at the site. We assume that it has been done the embankment of 10000 m3 on the road and according to the results of tests; there are 2 m3 of embankment as defects incompatible with our solution. We can calculate DPMO (Defects per million opportunities), Sigma Levels as follows:
DPMO = (2 / 10000) * 1000000 = 200
The number of DPMO can be converted to the Sigma level. For instance, in this example, 200 DPMO converts to slightly better than a 5 Sigma process.
Example (2): An Executive method for concrete placing (Cast - in - Place)
In Small building Sites
Define of the problem (D phase):
There is the lack of the executive method for concrete placing at small building sites. Since there is not a mechanized and automatic systems for concrete placing ( Cast - in - place ) in small building sites (included : Batching plant , Batch mixer , Truck mixer , … ) , a contractor has to utilizes from drum mixer or handling mixer by volume batching method . When you use the drum mixer, you cannot produce the fresh concrete in accordance with weight batching and standards. In fact, you have to use from the volume batching by scaling of a bushel so that you will lose the accuracy of your job and increase errors.
Measure phase (M):
Since we have the standards to prepare the formula of the concrete mix design by using of weight batching, I has tried to show changing of weight batching to volume batching of concrete materials (cement, water, aggregates) so that weight batching has already obtained by using of ACI 211 (Concrete Mix Design). In order to execute concrete placing (cast-in-place) at the sites, it is needed to be obtained a mix design of concrete.
A mix design of concrete (in accordance with ACI-211) introduces us only the weight batching of cement, water, aggregates.
We can use from weight batching, if we have had a batching plant, batch mixer, truck mixer…
In fact, if we have had a mechanized and automatic system for concrete placing, it can be used only in big and large sites.
But we have to use volume batching instead of weight batching in small sites. In this example, I have presented a method for changing of weight batching to volume batching in which we should measure the compressive strength and workability (slump) of fresh concrete as two important quality factors after using of this executive method.
Analysis phase (A):
The analysis of this method is included three following steps in which we need to determine the weight batching in accordance with ACI -211:
1) We should get the results of simple tests on aggregates as follows:
- Sieve analysis of coarse and fine aggregates
- Free unit weight of coarse aggregate
- Free unit weight of fine aggregate
- Free unit weight cement
2) According to above tests results and tables of ACI-211, we can estimate weight batching of concrete materials.
3) We assume weights batching of concrete materials per one cubic meter of the concrete in according with point (2) are as follows:
- Weight of coarse aggregate / 1 m3 concrete
- Weight of fine aggregate / 1 m3 concrete
- Weight of cement / 1 m3 concrete
- Weight of water / 1 m3 concrete
Improve phase (I):
In this phase, we should obtain the solution for the problem mentioned in the phase of Define (D). At the first, we should get the volume of a batch that it is available for us and total volume of Drum Mixer should be recognized that it depends on to type of Drum Mixer (It is Standard).
- Volume of an available batch
- Total Volume of Drum mixer (Volume capacity of Drum mixer)
According to above stated, we have:
- Free Unit weight of coarse aggregate
- Free Unit weight of fine aggregate
- Free Unit weight of Cement
- =1000 Kg / m3 Free Unit weight of Water
In this step, we can get the volume of each one of the concrete materials for one cubic meter of the concrete:
- The volume of coarse aggregate / 1 m3 concrete
- The volume of fine aggregate / 1 m3 concrete
- The volume of Cement / 1 m3 concrete
- The volume of Water / 1 m3 concrete
- Sum of concrete materials volumes
According to Volume of Drum Mixer, we should calculate the volume of concrete materials for one Drum Mixer batch:
- The volume of coarse aggregate / 1 unit Drum Mixer batch
- The volume of fine aggregate / 1 unit Drum Mixer batch
- The volume of Cement / 1 unit Drum Mixer batch
- The volume of Water / 1 unit Drum Mixer batch
We should get number of batches:
Number of total batches
Now, we can get number of batches for each material of the concrete with using of below formula:
Where:
- Each one of the concrete materials (aggregate, cement, water)
- Number of batches for each material of the concrete
- Number of total batches
- Weight of each one of the concrete material / 1 m3 concrete
(According to ACI-211 Tables)
- Free Unit weight of each one of concrete material
In here, I would like bring a sample as follows:
Sample:
According to ACI-211 Tables, we have obtained amount of materials per one cubic meter of the concrete as follows:
And so, free unit weight of above materials is below cited:
The volume of Drum Mixer and the Volume of the batch sample are:
Therefore, we have:
Number of Total batches
Now, we can calculate number of batches for each materials of the concrete:
Batches number of coarse aggregate
Batches number of fine aggregate
Batches number of Cement
Batches number of Water
According to above mentioned, we can execute concrete placing by using of ACI-211 or another standard and volume batching method in small sites where there is not any mechanized or automatic system.
Therefore, we can speak about optimum slump, W/C, quality of concrete even in small building sites.
Small building sites could be meant even when we are using of concrete in our homes.
But we should notice, for producing the concrete with high quality, all of aggregates, cement and water should be tested in laboratory before using of them.
Control phase (C):
In this phase, we should control our solution by preparing the samples of fresh concrete or to place the concrete as the real job at the site. We assume that we have executed about 5000 m3 of fresh concrete at the working place and according to the results of tests; there are 1.2 m3 of fresh concrete as defects incompatible with our solution. We can calculate DPMO (Defects per million opportunities), Sigma Levels as follows:
DPMO = (1.2/ 5000) * 1000000 = 240
The number of DPMO can be converted to the Sigma level. For instance, in this example, 240 DPMO converts to slightly better than a 5 Sigma process.
4.0 Conclusion
Regarding to the examples mentioned in this paper, there are many methods for solving of the problems. At the first, we should know if the problem is actually the problem . It means: Which problem should be solved by us? Further more, we should simplify the complex problem to be perceived easily. Besides,we should know that there are so many ways to solve the problem and we should choose the best one by balancing of Time and Energy (cost).
One of the best ways to solve the problems is to go along step by step as follows:
Step1) To find out exact definition of the problem.
Step2) To make a sentence that is exactly included all of the problem basic concepts (To summarize exact definition of the problem by a sentence).
Step3) To search the guiding channels of knowledge for each word or perfect sentence just like to use of the search engines.
Step4) To select of collected knowledge so that we find out the logical relation among them.
Step5) To find out assumptions, dependent and independent variables (unknowns) by using of Step (4).
Step6) To establish the differential equations by using of Step (5) and the points A to T mentioned in this paper.
Step7) To solve the differential equations by deleting of many variables (unknowns) so that we must observe balance of the Time and Energy (Cost).
Concerning to above steps, we can use of “Equilibrium Theory” for solving of the problems in the world. Maybe, one day we will be able to find out an opportunity of the Reference Frame with datum coordinates by using of Equilibrium Theory and Returning Analysis. We know that all of Equilibrium systems are the unstable and we must spend the energy for increasing of Equilibrium stability time.
Every project will smoothly move and be successfully fulfilled the least Time and Energy (Cost), if all of people involved in this project as well as know and accept the target of project. In the circumstances, the attractive concepts similar to Excessive Generosity, Hardworking, Perseverance, Honest, Reliable, Love, Truthfulness and so no will be raised. Of course, it is very hard because we have five cases as follows:
1)Training: All of people involved in the project should be familiar and learn about the target of the project.
2)To define the aim of the project (What is the problem): All of people involved in the project should accept the target of the project and it is very difficult (Actually, what is the problem?).
3) To choose the method for internal process. What is the best way to reach our target? How can we measure the best way?
4) Are all people satisfied with the target and output of the project?
What is our strategic plan to satisfy all people such as stakeholders, staff, customers, government, and so on?
5) What area our financial benefits to be obtained of outputs?